Webb15 mars 2016 · Use the difference of cubes identity to find: x^3-27 = (x-3)(x^2+3x+9) Both x^3 and 27=3^3 are perfect cubes. So we can use the difference of cubes identity: a^3-b^3 = (a-b)(a^2+ab+b^2) with a=x and b=3 as follows: x^3-27 =x^3-3^3 =(x-3)(x^2+x(3) + 3^2) =(x-3)(x^2+3x+9) This is as far as you can go with Real coefficients. If you allow Complex … Webb12 apr. 2024 · \sqrt{363} -3 \sqrt{27} asked by Anon. April 12, 2024. 11 answers. can you please show me how to do this equation im not really good with reading math but anything helps! answered ... Simplify the radical expression sqrt 56x^2 28x 2x sqrt 14*** 2x sqrt 7 sqrt 14x2 3. Simplify the radical expression. sqrt 490y^5w^6 2 sqrt 135y^2 2y ...
Solve x^3-x^2+1/3x-1/27 Microsoft Math Solver
WebbHow do you simplify trigonometry expressions? To simplify a trigonometry expression, use trigonometry identities to rewrite the expression in a simpler form. Trigonometry … Webb22 mars 2024 · Solution: Find a and b in the expression x^4 + ax^3 + 5x^2 + bx + 6. Solution: Given: f (x) = (x + 3) (x – 4) + 4. When f (x) is divided by (x – k), the remainder is k. Find k. Solution: Find the remainder if we divide 4y^3 + 18y^2 + 8y – 4 by (2y + 3) Solution: Find the quotient of 3x^5 – 4x^3 + 2x^2 + 36x + 48 divided by x^3 – 2x^2 + 6. in a truth table
Solve x3=27 Microsoft Math Solver
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